- #1

- 24

- 0

[tex]\int_0^1{\frac{(6ln4x)}{\sqrt{x}}dx[/tex] and I get as far as:

[tex]\lim_{b \to 0^+}{6\int_b^1{\frac{(ln4x)}{\sqrt{x}}[/tex]

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- Thread starter regnar
- Start date

- #1

- 24

- 0

[tex]\int_0^1{\frac{(6ln4x)}{\sqrt{x}}dx[/tex] and I get as far as:

[tex]\lim_{b \to 0^+}{6\int_b^1{\frac{(ln4x)}{\sqrt{x}}[/tex]

- #2

- 1,838

- 7

Substituting x = t^2 seems to work...

- #3

- 24

- 0

I'm not sure what you mean or where [tex]t^2[/tex] came from.

- #4

- 216

- 1

It's called substitution.

The substitution is [tex]t=\sqrt{x}[/tex] or [tex]t^2 = x [/tex]

The substitution is [tex]t=\sqrt{x}[/tex] or [tex]t^2 = x [/tex]

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