Improper Integrals

  • Thread starter regnar
  • Start date
  • #1
24
0
I've been stuck on this problem for quite some time and I get as far as setting up the problem. They are asking me to evaluate this integral:

[tex]\int_0^1{\frac{(6ln4x)}{\sqrt{x}}dx[/tex] and I get as far as:

[tex]\lim_{b \to 0^+}{6\int_b^1{\frac{(ln4x)}{\sqrt{x}}[/tex]
 

Answers and Replies

  • #2
1,838
7
Substituting x = t^2 seems to work...
 
  • #3
24
0
I'm not sure what you mean or where [tex]t^2[/tex] came from.
 
  • #4
216
1
It's called substitution.

The substitution is [tex]t=\sqrt{x}[/tex] or [tex]t^2 = x [/tex]
 

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