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Improper Integrals

  1. Jun 14, 2010 #1
    I've been stuck on this problem for quite some time and I get as far as setting up the problem. They are asking me to evaluate this integral:

    [tex]\int_0^1{\frac{(6ln4x)}{\sqrt{x}}dx[/tex] and I get as far as:

    [tex]\lim_{b \to 0^+}{6\int_b^1{\frac{(ln4x)}{\sqrt{x}}[/tex]
  2. jcsd
  3. Jun 14, 2010 #2
    Substituting x = t^2 seems to work...
  4. Jun 14, 2010 #3
    I'm not sure what you mean or where [tex]t^2[/tex] came from.
  5. Jun 14, 2010 #4
    It's called substitution.

    The substitution is [tex]t=\sqrt{x}[/tex] or [tex]t^2 = x [/tex]
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