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## Homework Statement

[itex]\int[/itex] (x-2)

^{-3/2}dx

## Homework Equations

[itex]\int[/itex]f(x)dx from 0 to ∞ = lim (t[itex]\rightarrow[/itex]∞) [itex]\int[/itex]f(x)dx from 0 to t

## The Attempt at a Solution

I have the solution from the solution manual, but I'm just not sure on one of the steps, after you substitute u=(x-2) and du=dx, then integrate u

^{-3/2}, but they say that the result to this step is lim(t[itex]\rightarrow[/itex]∞) -2(x-2)

^{-1/2}, that is when they integrate u

^{-3/2}they are getting a -2 coefficient, shouldn't it be a -2/3