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## Homework Statement

Note Diagram.

If they are released from rest, determine the time required for block A to attain a speed of 2 m/s. Neglect the mass of the ropes

## Homework Equations

## The Attempt at a Solution

I = mk

^{2}= (30)(.25

^{2}) = 1.875 kg m

^{2}

X Direction

mv + [tex]\int[/tex] Fdt = mv

_{2}

0 + O

_{x}t = 0

Y Direction

mv + [tex]\int[/tex] Fdt = mv

_{2}

0 + O

_{y}t - 30(9.81)t = 0

O

_{y}= 294.3

Moments

Iw

_{1}+ [tex]\int[/tex]M

_{O}dt = Iw

_{2}

0 + 25(.3) - 10(.18) = 1.875w

^{2}

w = [tex]\sqrt{3.04}[/tex]

How do i relate this to velocity and time. I can use v = wr, but how can i solve for t when v = 2 m/s

2 = .3w, therefore i need to find t when w = 2/.3