A 60g handball moving with a speed of 5m/s strikes the wall at a 40 degree angle with the norm, and then it bounces off with the same speed at the same angle with the norm. It is in contact with the for 2.0ms. a)What is the average force exerted by the ball on the wall? b)The rebounding ball is caught by a player who brings it to rest. In the process her hand moves back .50m. what is the impulse received by the player? c)what average force was exerted on the player by the ball? Impulse = change in momentum = m * change in velocity Avg force = Impulse / collision time Isn't velocity the same as speed but with a direction? So can vi = 5m/s and vf = -5m/s? The problem gave me an angle so I know I have to do something with it but I am not sure what. I try doing 60g * -10m/s as the impulse then divide it by 2ms for average force but it is wrong. Can someone help me.