Question: The 40 kg slider block is moving to the right with a speed of 1.5 m/s when it is acted upon by the forces F1 and F2. If these loadings vary as shown (in the attachment called graph), determine the speed of the block at t =6s. Neglect friction and the mass of the pulleys and cords. The graph doesn't really look like I drew it but you can get the picture (I hope). This is what I did so far: Equation: mV1 + summation (integral of) F * dt = mV2 So I calculated the area under each part of the graph and added them together like so 40*(1.5) + 30*(4-0) + 10*(6-4) + 10*(2-0) + 20*(4-2) + 40*(6-4) = 40V2 340 = 40V2 V2 = 8.5 m/s Is this right?