• Support PF! Buy your school textbooks, materials and every day products Here!

Impulse and Momentum Problem!

  • Thread starter bgaspar00
  • Start date
1
0
A grenade of mass 10 kg explodes into three pieces in the same plane, two of which, A (5.0 kg) and B (2.0 kg), move off as shown. Calculate the velocity of the 3.0 kg third piece, C.

I cannot show all of my work becuz it is basically just a sketch of what the diagram would look like, then drawing vectors and so on. However, i cannot get the right answer.
So heres the diagram it shows...
http://www.cbv.ns.ca/rv/physics/Physics12/BLM10-3.pdf


Δp = 0 where pi = 0

pix = pfx and piy = pfy






p1’



p1y’ = Cos30(5.0 kg (100.0 m/s))

= 433.013 kgm/s

p1x’ = Sin30(5.0(100m/s))
= 250


p2y’ = cos20 (2kg)(200 m/s)

= cos20 ( 400 kgm/s)

p2x’ = sin20 (400 kgm/s)




p1x’ + p2x’ + p3x’ = 0

500 + (- sin 20 (400 kgm/s)) + p3x’ = 0

p3x’ = 363.192 kgm/s

p1y’ + p2y’ + p3y’ = 0

500 kgm/s + (- cos 20(400 kgm/s)) + p3y’ = 0

p3y’ = 124.123kgm/s
p3 is found by resolving p3x’ and p3y’



p3x’

p3y’

p3

θ


p3^2 = [363.192kgm/s]2

+[124.123 kgm/s]2

|p3| = 383.816 kgm/s

θ = tan-1 [(124.123kgm/s)/(363.192kgm/s)]

= 19 degrees? wtf v3 = p3/m3

v3 = 383.816kgm/s/(3kg)

v3 = 128 m/s

This is completely wrong the answer is suppose to be V3= 128.92 m/s (S 82 E) or something....soo where did i go wrong? and is there an easier wayyyyy!!??
 

Answers and Replies

2,035
2
I'm denied permission to view the file.
 
79
0
I think you've mixed up your sines and cosines. The 'x' components should be cosine values, and the 'y' components should be sine values. To start you off, based on the picture:

Ax = - (500 cos 30)
Ay = 500 sin 30
 

Related Threads for: Impulse and Momentum Problem!

  • Last Post
Replies
0
Views
828
  • Last Post
Replies
3
Views
844
  • Last Post
Replies
1
Views
5K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
5
Views
4K
  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
3
Views
1K
Replies
3
Views
929
Top