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Impulse and Momentum Problem

  1. Aug 6, 2009 #1
    1. The problem statement, all variables and given/known data

    From Cutnell & Johnson PHYSICS 7th Edition Textbook - Ch 7 / Problem #1

    One average force F1 has a magnitude that is three times as large as that of another average force F2. Both forces produce the same impulse. The average force F1 acts for a time interval of 3.2 ms. For what time interval does the average force F2 act?

    2. Relevant equations

    Note sure. I think...Impulse-Momentum Theorem

    Ft = mvf - mvo

    3. The attempt at a solution

    No serious attempt made. I get tripped up in the wording of the problem. Any help would be appreciated.

    Thanks!
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Aug 6, 2009 #2

    kuruman

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    The impulse is the product F*t as you say. If the impulses for the two forces are the same, we can say this with an equation. Use this to say that Impulse 1 is the same as Impulse 2 with an equation.
     
  4. Aug 6, 2009 #3
    Thanks for the explanation, though truthfully I'm still not getting it...
     
  5. Aug 6, 2009 #4

    kuruman

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    Let's try this.

    Impulse 1 = F1t1
    Impulse 2 = F2t2

    The problem says the impulses are equal. This means that

    F1t1=F2t2

    Can you finish from here? Don't forget to say with an equation that F1 is three times F2.
     
  6. Aug 6, 2009 #5
    I'm inclined to write it as:

    (3F1t1) = (F2t2)

    Still thinking about the next step...
     
  7. Aug 6, 2009 #6

    kuruman

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    You replaced F1 with three times itself. Can F1 be the same as 3F1? What is F1 the same as? Re-read the question.
     
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