1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Impulse and momentum

  1. Mar 31, 2009 #1
    1. The problem statement, all variables and given/known data


    A golfer hits a golf ball of mass 0.045 kg the ball over some short trees. He hits the ball at
    an angle of 60(degrees) to the horizontal and it travels a horizontal distance (Range) of 60.0 m in a time of 8.00 s. The golf club of mass 0.60 kg is in contact with the ball for a time of 2.40 ms.
    (a) What is the average impulsive force on the golf ball?
    (b) What is the average impulsive force on the golf club?
    (c) What is the change in momentum of the golf club?

    2. Relevant equations
    All my answers are exactly have of what my teacher posted. My answer for (a) should be 280N, (b) should be -280N, and (c) should be -0.67 kg m/s


    3. The attempt at a solution
    Since the ball is hit at an angle, I split the momentum into x and y components. Initial velocity is zero, so both x1 and y1 are zero.
    (a) The final momentum for x would be: mvcos(theta) = (0.045kg)(7.5m/s)(cos(60))= 0.169 kg m/s

    The final momentum for y would be: mvsin(theta) = (0.045kg)(7.5m/s)(sin(60))= 0.29 kg m/s
    Divide both values by the time the force was in contact (2.5 ms).
    So to find the average impulsive force, take both values of momentum divided by time and find the magnitude: [(70.4)^2 + (121)^2]^0.5 = 140 N

    (b) it would just be the opposite of the force on the golf ball, -140N
    (c) change in momentum would just take the magnitude of the the momentum:
    [(0.169)^2 + (0.29)^2]^0.5 = -0.33 kg m/s (negative because its the change in momentum of the golf club not the golf ball)
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Mar 31, 2009 #2

    LowlyPion

    User Avatar
    Homework Helper

    I might note that the 60m/8s is just the x component of velocity, not the initial x,y velocity of the ball.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Impulse and momentum
  1. Impulse momentum (Replies: 5)

  2. Momentum and Impulse (Replies: 5)

Loading...