1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Impulse and weight problem

  1. Nov 26, 2012 #1
    1. The problem statement, all variables and given/known data

    A pickup truck has a mass of 2400 kg when empty. It is driven onto a scale, and sand is poured in at the rate of 150 kg/s from a height of 3.0 m above the truck bed. At the instant when 440 kg of sand have already been added, what weight does the scale report?

    2. Relevant equations

    $$ J=\Delta p=mv_1-mv_0 $$
    $$ w=mg $$

    3. The attempt at a solution

    I can't quite see what this has to do with impulse, and whether or not kinematics have to be used in this at all or not.
     
  2. jcsd
  3. Nov 26, 2012 #2
    What is the velocity of the sand after it has dropped the 3 m? What is the rate of change of momentum of the stream of sand when it hits the truck bed?
     
  4. Nov 26, 2012 #3
    Well, would we use the fact that initial velocity is zero and final is the unknown, the acceleration downward is that of gravity, which is -9.8 m/s^2, and the displacement is 3.0 m so you would use $$ v^2=v_0^2+2a\Delta y $$ to find the velocity?

    And, if the initial velocity is zero, then the change of momentum would just be the mass times the velocity calculated above, correct?
     
  5. Nov 26, 2012 #4
    Correct on getting the velocity of the sand when it hits the bed. The downward velocity of the sand then goes to zero. If the rate of sand flow is 150 kg/sec, and its velocity goes from v to zero when it hits the bed, what is the rate of change of momentum of the sand which hits the bed?
     
  6. Nov 26, 2012 #5
    So solving for v by putting in

    $$ v^2=2(9.8 m/s^2)(3.0 m) $$

    we get 7.7 meters per second.

    So, if I'm correct, the formula for rate of change of momentum would be the force, which is equal to the change in momentum, Δp, over the change in time, which is Δt. We can calculate change in time by taking the mass of sand, which is 440 kg, and dividing it by the rate, 150 kg/s, to get 2.9 s. So the change in momentum at the top is just mass of the pickup truck, 2400 kg, plus the 440 kg, times the velocity I calculated, 7.7 m/s, and since it goes to zero, the final momentum is zero.
     
  7. Nov 26, 2012 #6
    Not quite. If the rate at which the sand is hitting the bed is 150 kg/sec, and its velocity decreases from 7.7 m/s to zero when it hits the bed, the rate of change of momentum for the sand stream hitting the bed is 150 x 7.7 = 1155N. The mass of the truck is 2400 kg, and, when 440 kg of sand is already at rest in the bed, the total mass of truck + sand at rest = 2840 kg. Therefore, the total force measured by the scale = 2840 (9.8) + 1155 Newtons.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Impulse and weight problem
  1. Impulse problem (Replies: 6)

  2. Impulse problem (Replies: 1)

  3. Impulse problem (Replies: 2)

  4. Impulse Problem (Replies: 6)

  5. Impulse Problem (Replies: 1)

Loading...