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Impulse bouncing ball

  1. Nov 10, 2009 #1
    1. The problem statement, all variables and given/known data
    To make a bounce pass, a player throws a 0.60 kg basketball towards the floor. the ball hits the floor with a speed of 5.4m/s at an angle of 65o to the vertical. The ball rebounds elastically with the same speed and angle. Calculate impulse (magnitude and direction) delivered to the ball by the floor.


    2. Relevant equations
    if ^ is delta
    I=^P

    3. The attempt at a solution

    ^Vx=0

    ^Vy=Vyf-Vyi=

    5.4m/s(cos(65o)+5.4m/s(cos(65o)

    Impulse= ^P

    I just want to confirm that the impulse delivered to the ball will all be directed vertically upward because ^Vx=0. So the angle of collision will have no effect on the direction of impulse in this case.
     
  2. jcsd
  3. Nov 10, 2009 #2

    rl.bhat

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    Homework Helper

    The direction remains the same, but the magnitude depends on the angle.
     
  4. Nov 11, 2009 #3
    Thank you
     
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