1. The problem statement, all variables and given/known data 2000kg stationary cannon 25kg cannon ball fired horizontally @ 250m/s Assume no friction acting on the cannon ***What is the velocity of the cannon after firing the ball? 2. Relevant equations PT = PT’ ^initial momentum = final momentum m1v1 + m2v2 = m1v1’ + m2v2’ 3. The attempt at a solution m1v1 + m2v2 = m1v1’ + m2v2’ (2000kg)(0m/s) + (25kg)(0m/s) = (2000kg)(v1’) + (25kg)(250m/s) 0 = (2000kg)(v1’) + 6250kg•m/s v1’ = (–6250kg•m/s)/(2000kg) v1’ = –3.125m/s After rounding: v1’ = –3.1m/s Therefore, the velocity of the cannon after firing the cannonball is 3.1m/s[backward] I think I got it.. if someone could confirm my answer for me that would be awesome! thank you forum!