# Impulse/momentum check

1. Dec 9, 2008

### DollarBill

1. The problem statement, all variables and given/known data
http://img401.imageshack.us/img401/46/impulsemw6.jpg [Broken]

Before the force is applied (t<0), the particle moves along the x axis with a velocity of -6.3 m/s.

Find the velocity of the particle after the force stops acting on it.

The particle has a mass of 5.2 kg

2. Relevant equations
j=$$\Delta$$p
$$\Delta$$p=0

3. The attempt at a solution
j=42Ns

j=$$\Delta$$p
42=mvF-mv0
42=(5.2)vF-5.2(-6.3)
9.24=5.2(v)F
vF=1.777 m/s

Last edited by a moderator: May 3, 2017
2. Dec 9, 2008