You are standing on a large sheet of frictionless ice and are holding a large rock. In order to get off the ice, you throw the rock so it has velocity relative to the earth of 11.3 m/s at an angle of 34 above the horizontal. Your mass is 67.0 kg and the rock's mass is 14.4 kg.
What is the magnitude of the impulse on the Earth as a result of this throw?
J = p_2 - p_1
The Attempt at a Solution
The first part of the question had me find the speed of me after the throw.
mmevme = mrockvrock
67(v) = 14.4(11.3cos34)
v= 2.01 m/s
Now i am asked to find the impulse as stated above.
I thought the impulse would just be zero since momentum of this is conserved but i was wrong.
Can anyone help me with this please?
Thank you :)