Stick of mass M resting on frictional surface with friction coefficients μk=μs. From the center of the stick at time t=0 a ball of mass m thrown to the right with an angle θ above the horizontal and with speed v0. As a result of the throwing there is an impulse on the y axis (perpendicular to the horizontal stick) between the stick and the surface for short time Δt.
Calculate the impulse of the normal force between the surface and the stick. Assume the interaction time is short Δt→0?
How am I formulate the equation- 1. When I calculate the change in momentum is pf=0 because the stick does not move vertically? 2. Is the acting force on the stick is F=N(t)−Mg because the normal on M by the ball is internal force?