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Impulse on a golf ball

  1. Oct 21, 2007 #1
    1. The problem statement, all variables and given/known data
    A golf ball with a mass of 43.80 g can be blasted from rest to a speed of 64.60 m/s during impact with a club head. Assume that the impact lasts only about 0.980 ms. Calculate the change in momentum of the ball.


    2. Relevant equations
    P = mv
    Change in P = Pf - Pi
    J = 1/2 base * height
    Favg = J/Change in time

    3. The attempt at a solution
    Mg = .04380kg
    Vi = 0m/s
    Vf = 64.60m/s
    Time = .00098s

    A.) Change in P = (.04380kg * 64.60m/s) - (.04380kg - 0m/s) = 2.83kg*m/s RIGHT
    B.) J = 1/2 * 0.00098s * 2.83kg*m/s = .001386
    Favg = (0.001386N/s)/(0.00098s) = 1.415N WRONG...But I don't know why. I think it has to do with when I calculated J I am not sure if my height (Fmax) is supposed to be the 2.83kg*m/s.
     
  2. jcsd
  3. Oct 21, 2007 #2
    Okay maybe I don't need Fmax is J = Change in P??
     
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