glasgowm said:A cue exerts an average force of 7N on a stationary snooker ball of mass 200g if the impact lasts for 45ms, with what speed does the ball leave the que?
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Ft = mv - mu
F = m(v-u/t)
F = 0.2(v-0/0.0045)
= 0.2v/0.0045 = 44.4444V
Can't figure out what the next step is from my notes.
Cheers
I already did that.radou said:Simply stated, the impulse equals the change of linear momentum, so, you have: [tex]F\cdot t = mv_{2}-mv_{1}[/tex], where m is the mass of the ball, v2 the final velocity and v1 the initial velocity (equals zero). From this equation you can easily retrieve v2.
glasgowm said:I already did that.
The force of a snooker ball can be calculated by multiplying its mass by its acceleration. This can be represented by the formula F = m x a, where F is the force, m is the mass, and a is the acceleration.
The unit used to measure force is Newtons (N).
The speed of a snooker ball can be calculated by dividing the distance it travels by the amount of time it takes to travel that distance. This can be represented by the formula v = d/t, where v is the speed, d is the distance, and t is the time.
The unit used to measure speed is meters per second (m/s).
The force and speed of a snooker ball can be affected by factors such as the mass of the ball, the angle and force of the cue, the friction of the table, and any external forces such as air resistance or collisions with other balls.