1. The problem statement, all variables and given/known data Two small bodies A and B with masses 1kg and 2kg respectively are placed side-by-side on a smoooth horizontal table and are joined by a light inealstic string. A is projected horizontally away form B with a velocity of 6m/s. i)Determine the speed of B after the string becomes taut, ii)the impulsive tension in the string, iii)and the loss in kinetic engergy at this stage. 2. Relevant equations 3. The attempt at a solution got all three parts ok, but i dont follow the answer for part ii (and in my opinion not understanding is just as bad as getting the wrong answer). in my notes i have... v = 0 u = 2m/s (from i) Impulsive Energy: For B: 2u = T 2(2) = T T = 4N/s why is this only calculated for B? Since it's the energy in the string I thought it would be the energy in the whole system? or some sort of balance? In the lecture notes example it seems the impulse is only calculated for the other particle in the system. why? also what would happen if you had 3+ particles in the system?