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Impusle of golf ball

  1. Feb 3, 2005 #1
    A golf ball (m=46g) is struck a blow that makes an angle of 45 degrees with the horizontal. The ball lands 200 m away on a flat fairway. If the golf club and ball are in contact for 7 milliseconds, what is the average force of impact neglecting air resistance.

    Here’s what I did.

    [tex]d=\frac{v^2sin2\theta}{g}[/tex]
    [tex]200m=\frac{v^2sin90}{g}[/tex]
    [tex]1960=v^2[/tex]
    [tex]v=44.3m/s[/tex]

    [tex]I=mv-mv[/tex]
    [tex]I=0.046kg*44.3m/s[/tex]
    [tex]I=2.04Ns[/tex]

    [tex]I=Ft[/tex]
    [tex] 2.04Ns =F(0.007s)[/tex]
    [tex]F=291.4N[/tex]

    Is this correct?
     
    Last edited: Feb 3, 2005
  2. jcsd
  3. Feb 3, 2005 #2

    Doc Al

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    Staff: Mentor

    I didn't check your arithmetic, but your method is correct.
     
  4. Feb 3, 2005 #3

    Andrew Mason

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    Science Advisor
    Homework Helper

    You ususally use a pitching wedge to get a 45 degree angle. 45 degrees - 200 m? That is some wedge shot.

    AM
     
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