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A golf ball (m=46g) is struck a blow that makes an angle of 45 degrees with the horizontal. The ball lands 200 m away on a flat fairway. If the golf club and ball are in contact for 7 milliseconds, what is the average force of impact neglecting air resistance.

Here’s what I did.

[tex]d=\frac{v^2sin2\theta}{g}[/tex]

[tex]200m=\frac{v^2sin90}{g}[/tex]

[tex]1960=v^2[/tex]

[tex]v=44.3m/s[/tex]

[tex]I=mv-mv[/tex]

[tex]I=0.046kg*44.3m/s[/tex]

[tex]I=2.04Ns[/tex]

[tex]I=Ft[/tex]

[tex] 2.04Ns =F(0.007s)[/tex]

[tex]F=291.4N[/tex]

Is this correct?

Here’s what I did.

[tex]d=\frac{v^2sin2\theta}{g}[/tex]

[tex]200m=\frac{v^2sin90}{g}[/tex]

[tex]1960=v^2[/tex]

[tex]v=44.3m/s[/tex]

[tex]I=mv-mv[/tex]

[tex]I=0.046kg*44.3m/s[/tex]

[tex]I=2.04Ns[/tex]

[tex]I=Ft[/tex]

[tex] 2.04Ns =F(0.007s)[/tex]

[tex]F=291.4N[/tex]

Is this correct?

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