Impusle of golf ball

  • #1
1,197
1
A golf ball (m=46g) is struck a blow that makes an angle of 45 degrees with the horizontal. The ball lands 200 m away on a flat fairway. If the golf club and ball are in contact for 7 milliseconds, what is the average force of impact neglecting air resistance.

Here’s what I did.

[tex]d=\frac{v^2sin2\theta}{g}[/tex]
[tex]200m=\frac{v^2sin90}{g}[/tex]
[tex]1960=v^2[/tex]
[tex]v=44.3m/s[/tex]

[tex]I=mv-mv[/tex]
[tex]I=0.046kg*44.3m/s[/tex]
[tex]I=2.04Ns[/tex]

[tex]I=Ft[/tex]
[tex] 2.04Ns =F(0.007s)[/tex]
[tex]F=291.4N[/tex]

Is this correct?
 
Last edited:

Answers and Replies

  • #2
Doc Al
Mentor
45,250
1,601
I didn't check your arithmetic, but your method is correct.
 
  • #3
Andrew Mason
Science Advisor
Homework Helper
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403
You ususally use a pitching wedge to get a 45 degree angle. 45 degrees - 200 m? That is some wedge shot.

AM
 

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