In a particle accelerator...

  1. Heres one more question


    In a particle accelerator, an alpha particle with a mass of 6.64 x10^-27 kg is moving with a speed of 2.50x10^7 m/s. It is moving perpendicularily through a magnetic field of intensity 0.150 T. Using appropriote equations and method find the radius of curvature of its path.

    I'm completly stumped on this HW question due tomorrow, I'm looking through my notes for an equation for this. Also I have no idea how to find the radius of the curvature.

    PLEASE HELP.
     
  2. jcsd
  3. dextercioby

    dextercioby 12,308
    Science Advisor
    Homework Helper

    HINT:The particle moves in a circle.The Lorentz magnetic force is a centripetal force.

    Daniel.
     
  4. umm...

    whats the formula for the lorentz magnetic force? I thought it was like...

    F=qv+B

    I dont see how that helps. Could you help me out a bit more? I need to get this one before tonight.
     
  5. krab

    krab 905
    Science Advisor

    The point is that it is a force prependicular to velocity. That means that it compels the particle to travel in a circle. Equate it to the formula for the centrifugal force.
     
  6. dextercioby

    dextercioby 12,308
    Science Advisor
    Homework Helper

    Nope,it's
    [tex] \vec{F}_{mag,L}=q\vec{v}\times\vec{B} [/tex]
    The centripetal force is:
    [tex] \vec{F}_{cp}=\frac{m\vec{v}^{2}}{r^{2}}\vec{r} [/tex]


    Daniel.
     
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