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In Need of Help with a Simple Calculus Question that has me Stumped (PLEASE HELP)

  1. May 27, 2012 #1
    1. The problem statement, all variables and given/known data

    Simplify
    ln [(e^1-3ln2)/(2∏/e)]

    2. Relevant equations

    I was using the equation e^lnx = x to try and simplify the numerator, but I am unsure if that is correct.

    3. The attempt at a solution

    I am very rusty with my calculus and when it comes to using ln, I tend to get stumped with the question.
    I had simplified the numerator to -5 using e^lnx = x, but I was very unsure if this is correct; I may be making up rules of my own.
    The denominator was simplified to 2∏(e^-1)
    The entire fraction was then ln (-5/(2∏(e^-1)) and I couldn't figure out what to do next with this.
     
    Last edited: May 27, 2012
  2. jcsd
  3. May 27, 2012 #2

    SammyS

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    Hello Tweedybird. Welcome to PF !

    If what you have is indeed
    [itex]\displaystyle \ln \left(\frac{e^1-3\ln(2)}{2\pi/e}\right)[/itex]​
    then you are very far off.

    Perhaps you meant
    [itex]\displaystyle \ln \left(\frac{e^{1-3\ln(2)}}{2\pi/e}\right)\ .[/itex]​

    Well ... there's still a problem.
     
  4. May 27, 2012 #3

    The second one is exactly the question I need help with! Sorry for the confusion, but I'm not sure why there is a problem with it, it is in my textbook as a question to be simplified!
     
  5. May 27, 2012 #4

    SammyS

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    Review properties of logarithms & exponents.

    One property that you may find helpful is:
    [itex]\displaystyle \ln\left(\frac{A}{B}\right)=\ln(A)-\ln(B)[/itex]​
     
  6. May 28, 2012 #5
    I figured the question out! A little review and that hint helped me out quite a bit! Like I said in my post, I am a little rusty with this subject! Thank you for your help :)
     
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