1. The problem statement, all variables and given/known data A 2.00 kg block is held in equilibrium on an incline of angle = 75° by a horizontal force applied in the direction shown in Figure P4.50. If the coefficient of static friction between block and incline is µs = 0.300, determine the following. (a) the minimum value of F (b) the normal force exerted by the incline on the block Illustration of Problem: http://www.webassign.net/sercp/p4-50.gif... 2. Relevant equations F=ma 3. The attempt at a solution For Y Component: n-mgcos75=0 n=mgcos75 n=2.00*9.8cos75 n=5.07 N It says this is wrong because of: Your answer differs from the correct answer by orders of magnitude. For X F-fs=0 F=usn=0 F=usn F=0.300 x 5.07 N = 1.52 N Does this look like I did it correctly?