Incline Problem with spring

In summary, to find the launching speed of a 100-g ball from a ball launcher in a pinball machine with a spring of force constant 1.20 N/cm and an inclined surface of 10.0°, use the concept of conservation of energy. The initial energy of the compressed spring is equal to the energy of the ball, which is given by (1/2)mv^2 + mgh. Solving for v gives a launching speed of 1.68 m/s.
  • #1
dareupgang
3
0

Homework Statement



The ball launcher in a pinball machine has a spring that
has a force constant of 1.20 N/cm The surface
on which the ball moves is inclined 10.0° with respect
to the horizontal. If the spring is initially compressed
5.00 cm, find the launching speed of a 100-g ball when the
plunger is released. Friction and the mass of the plunger negligible

Homework Equations



Ki + Ws + Wg = Kf


The Attempt at a Solution



W = integral kx
but i don't understand where gravity comes into play. I'm trying to understand the concept, the solution manual works it out as 1.68 m/s and they use cos 100 don't understand that either
 
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  • #2
I would do this problem by using conservation of energy. The energy in a spring is given by E = (1/2)kx^2, so plugging in your spring constant and initial compression gives you the initial energy, Ei.

Now all that energy goes into the pinball. The energy of the pinball is given by E = (1/2)mv^2 + mgh, where h is altitude. (There's where the gravitational acceleration comes into play). That's the final energy, Ef. Just equate Ei and Ef and then solve for v. h will represent the difference in altitude between the compressed position and the equillibrium position--so h=5cos(10°).
 

1. What is the "Incline Problem with spring"?

The "Incline Problem with spring" is a classic physics problem that involves a block placed on an inclined plane with a spring attached to it. The block will slide down the incline due to the force of gravity, but the spring will exert an opposing force, creating a system of forces that must be analyzed.

2. How do you calculate the forces involved in the "Incline Problem with spring"?

To calculate the forces involved in the "Incline Problem with spring", you must first draw a free-body diagram and identify all the forces acting on the block. These forces include the force of gravity, the normal force, and the force of the spring. Then, you can use Newton's second law (F=ma) to calculate the net force on the block.

3. What is the equilibrium position in the "Incline Problem with spring"?

The equilibrium position in the "Incline Problem with spring" is the point where the block comes to rest and the spring is neither compressed nor extended. At this point, the forces acting on the block are balanced, and there is no acceleration.

4. How does the angle of the incline affect the motion of the block in the "Incline Problem with spring"?

The angle of the incline affects the motion of the block in the "Incline Problem with spring" by changing the force of gravity acting on the block. As the angle of the incline increases, the force of gravity acting on the block will also increase, causing it to accelerate down the incline at a faster rate.

5. What happens to the block and spring when the incline angle is decreased to 0 degrees in the "Incline Problem with spring"?

If the incline angle is decreased to 0 degrees in the "Incline Problem with spring", the block will not move as there is no component of the force of gravity acting down the incline. The spring will also not exert any force as it is not compressed or extended. This is known as the static equilibrium position.

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