1. The problem statement, all variables and given/known data Imagine a ramp on a 30deg incline with a 1kg mass on top of it. mu kinetic coefficient is .25 between the mass and the ramp. A person applies a horizontal force of 10N to the 1kg mass on the incline ramp opposite to the direction of acceleration. What is the normal force acting on the mass? 2. Relevant equations Ff=uFn Trig functions sin and cosine i think but not sure. 3. The attempt at a solution I figured the normal force to be 9.8cos 30deg = 8.5N I figured the force along the ramp in the direction of the acceleration to be 9.8sin 30deg=4.9N I got the force friction to be .25*8.5=2.1N I'm lost ....don't know what i am doing wrong because they gave an answer of 13.5N for the normal force acting on the mass. Please help?