Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Intro Physics Homework Help
Advanced Physics Homework Help
Precalculus Homework Help
Calculus Homework Help
Bio/Chem Homework Help
Engineering Homework Help
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Homework Help
Engineering and Comp Sci Homework Help
How do I calculate the forces on an incline with given parameters?
Reply to thread
Message
[QUOTE="lecammm, post: 4495540, member: 487247"] As given by the attached question, we are given: [LIST=1] [*]The force on the pulley, 51N [*]The angle of the pulley, 31 degrees [*]The mass of the box, 15 kg [*]The angle of the incline, 31 degrees [*]The kinetic friction coefficient, 0.5 [/LIST] I think the relevant equations are: ƩFy = 0; ƩFx = ma; F(friction) = N*μ My attempt of the solution involved choosing my axis to be parallel to the slope (x axis) and y-axis perpendicular to the slope, then breaking the 51N force on the pulley up into it's components, i.e; for x direction: 51cos(31) for y direction: 51sin(31) Then break up the boxes weight force into x & y components, i.e. for x direction: (15*9.81)*cos(31) for y direction: (15*9.81)*sin(31) Next I summed the forces in the y direction to find the normal force N i.e. [B]ƩFy = -(15*9.81*sin(31))+N+51(sin(31) = 0[/B] Giving [B]N = 49.521[/B] Next I found the force for friction giving: [B]F = 49.521*0.5 F = 24.7605[/B] So then I tried to calculate the forces in the x direction with the positive direction being up the slope ƩFx = 24.7605 + 51cos(31) + T - (15*9.81)*cos(31) + F = 15 * a However I do not know where to find T, or if any of this working is correct, I'd really like some guidance on where to go from here, thanks. [/QUOTE]
Insert quotes…
Post reply
Forums
Homework Help
Engineering and Comp Sci Homework Help
How do I calculate the forces on an incline with given parameters?
Back
Top