1. The problem statement, all variables and given/known data A sight seen on many bunny hills across ontatrio is young skiers pushing on ski poles and gliding down a slope untill they come to a rest . Obeserving from a distance , you note a young person (approximatly 25kg) pushing off with the ski poles to give herself an intial velocity of 3.5m/s. If the inclination of the hills is 5 degress and hte coefficient of kinetic friction for the skis on dry snow is 0.20 calculate. A) the time taken for the skier to come to a stop 2. Relevant equations solving for t a=v/t solving for a a=Fnet/m 3. The attempt at a solution vi-3.5m/s m=25kg mu=0.20 angle=5degress I'm assuming that the skier without velocity would be stationary on the inclination. This is my first problem, is she accelerating down the ramp or moving at a constant velocity Fg =mg=25kg(9.8m/s^2)=245N Fn=Fg-Fy=mg-mgsin5=25kg(9.8m/s^2)-25kg(9.8m/s^2)sine5=224N Fg=245N Fn=224N Ff=muFn=0.20mgcos5=49N 49 newtons on the yaxis This is where I'm confused I have another equation that goes like this Fa=Fgsine5 + muFn =masine5+mumascos5 =ma(sine +mucos5) -25kg(9.8m/s^2)(sine5+0.20(cos5)) =70N I'm assuming this equation accounts for acceleration, subtracting the Ff. Fnet=x+y=21+70 =91N a=91/25=3.64m/s^2 t=3.5m/s/3.64m/s^2=0.9s This is wrong oh and can someoen give me a more detailed explaantion what Fnormal is. I"m assuming it is the x component Fg subtracted from Fg.