1. The problem statement, all variables and given/known data A skateboarder slides down a frictionless ramp inclined at an angle of 30° to the horizontal. He then slides across a frictionless horizontal floor and begins to slide up a second incline at an angle of 25° to the horizontal. The skateboarder starts at a distance of 10 m from the bottom of the first incline.How far up the second incline will he go if the coefficient of kinetic friction on the second incline is 0.10? 2. Relevant equations Fnet=ma a=gsin(theta) 3. The attempt at a solution So I got the first part right-- I found V2 to be 9.9 m/s. So for the second ramp, I used the formula Fnet=F(parallel)-u(Fn). ma=mgsin25 deg. -0.1(cos 25 deg.) I got an acceleration of 0.33 m/s^2, but the answer at the back is different. Also, I don't know whether g should be positive or negative. Thanks in advance!