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## Homework Statement

A 3.00 kg block starts from rest and slides a distance d down a frictionless 30.0° incline. While sliding, it comes into contact with an unstressed spring of negligible mass. The mass slides an additional 0.219 m as it is brought momentarily to rest by compression of the spring (k = 400 N/m). Find the initial separation d between mass and spring.

## Homework Equations

Kinetic energy: mv^2/2-mu^2/2

Potential energy of a spring: kx^2/2

ΔK=-ΔU

Δx=Vt+0.5at^2

V=Vo+at

## The Attempt at a Solution

kx^2/2=mv^2/2

400(0.219^2)=3v^2

v=2.529 m/s

a=9.8sin(30°)

2.529=4.9t

t=0.516

x=2.45*0.516^2

x=0.653

The answer is wrong, haha. But that is what I did, help me?

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