1. The problem statement, all variables and given/known data A 3.00 kg block starts from rest and slides a distance d down a frictionless 30.0° incline. While sliding, it comes into contact with an unstressed spring of negligible mass. The mass slides an additional 0.219 m as it is brought momentarily to rest by compression of the spring (k = 400 N/m). Find the initial separation d between mass and spring. 2. Relevant equations Kinetic energy: mv^2/2-mu^2/2 Potential energy of a spring: kx^2/2 ΔK=-ΔU Δx=Vt+0.5at^2 V=Vo+at 3. The attempt at a solution kx^2/2=mv^2/2 400(0.219^2)=3v^2 v=2.529 m/s a=9.8sin(30°) 2.529=4.9t t=0.516 x=2.45*0.516^2 x=0.653 The answer is wrong, haha. But that is what I did, help me?