A block (starting from rest) with mass m = 4.5 kg slides down a frictionless incline a distance of d = 3m and then slides across a horizontal floor with friction (the coefficient of friction is Fk = 0.52). The speed of the block at the bottom of the incline is v1 = 7m/s. What is the angle of the incline? (Assume the acceleration was constant.)
v initial = 0
mgsin(mu) - ƒk = ma
The Attempt at a Solution
I am wondering if I am approaching this correctly.
mgsin(theta) - ƒk = ma