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Inclined plane

  1. May 11, 2009 #1
    1. The problem statement, all variables and given/known data

    A block (starting from rest) with mass m = 4.5 kg slides down a frictionless incline a distance of d = 3m and then slides across a horizontal floor with friction (the coefficient of friction is Fk = 0.52). The speed of the block at the bottom of the incline is v1 = 7m/s. What is the angle of the incline? (Assume the acceleration was constant.)

    2. Relevant equations
    v initial = 0
    mgsin(mu) - ƒk = ma

    3. The attempt at a solution
    I am wondering if I am approaching this correctly.
    mgsin(theta) - ƒk = ma
    Last edited: May 11, 2009
  2. jcsd
  3. May 11, 2009 #2


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    I hope you mean mgsinθ.

    I would be concerned if you were trying to plug in μ, usually used for the coefficient of friction, as the angle.
  4. May 11, 2009 #3
    sorry -- that's what I meant. All the greek letters -- uggh.
  5. May 11, 2009 #4


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    As to the problem, the equation you have doesn't address the basic acceleration down the incline, if your statement of the problem is correct in saying the incline is frictionless.
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