The problem states: A horizontal force of 77 N pushes a 12 kg block up a frictionless incline that makes an angle of 60 degrees with the horizontal. What is the normal force that the incline exerts on the block? After drawing the FBD I can see there are only 2 forces acting in the Y direction which are Fn and W. so Fn = mg cos theta = 12 kg ( 9.81 m/s^2) * cos (60 deg) = 58.86 N. This is a homework problem and when attempting to submit the problem on webassign it keeps telling me it is incorrect. I am not sure where I am going wrong or if there is an error with the problem. Thanks.