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Inclined rotating drum

  1. Mar 30, 2014 #1
    1. The problem statement, all variables and given/known data
    I am basically designing a rotary drum dryer and need to know the positions of the bearings for the dryer to be stable.
    The drum is of length 17 m with diameter 3.24 m, inclined at 2° rotating at 3.24 rpm. I need to find the distance X and OY. (Given that Y passes through the center of mass) Weight of the drum =280 kN

    http://https://scontent-a-kul.xx.fbcdn.net/hphotos-ash3/t31.0-8/p417x417/10014962_10152301201595569_2033873904_o.jpg [Broken]

    2. Relevant equations

    Moment= F x D = WD ;
    Moment CW = Moment ACW


    3. The attempt at a solution
    I am trying to solve this using moments. But I am stuck with finding the centre of mass of the inclined cylinder.

    According to me (and after reading alignments of rotary drum, they did not take into consideration the inclination), X can be found by : (17/2)/2 =4.25m (Is that possible?)
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
    Last edited by a moderator: May 6, 2017
  2. jcsd
  3. Mar 30, 2014 #2

    CWatters

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    Homework Helper

    Not sure I will be around over the next few days to help but I suggest you post a diagram providing more detail such as roughly where the bearings are.

    Are these the bearings that the drum spins in OR the bearings that the drum pivots about when changing inclination to tip the contents out or ??

    2 degrees is quite a small angle.. not far off horizontal..so why do you think it needs to be taken into account?

    Finding the centre of mass of an inclined cylinder is quite trivial. So I think you might be asking the wrong question?

    Lets say that the drum is uniform and the centre of mass is mid way between the ends when viewed horizontally (eg 17/2 = 8.5m from one end). Then when inclined it will still be mid way between the ends when inclined. See diagram.

    A = 0.5*17*Cos(0) = 8.5m
    B = 0.5*17*Cos(2) = 8.4948m

    Similarly if the centre of mass is say 1/3rd of the way from one end.
     

    Attached Files:

  4. Mar 30, 2014 #3

    CWatters

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    PS. Just noticed you tried to post a diagram but I can't see it or open it.
     
  5. Mar 30, 2014 #4

    NascentOxygen

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    Staff: Mentor

    This being the homework forum, PF rules stipulate that only assistance to understanding should be given, not a complete solution to any problem posted.

    Sook's pic:

    https://scontent-a-kul.xx.fbcdn.net/hphotos-ash3/t31.0-8/p417x417/10014962_10152301201595569_2033873904_o.jpg
     
    Last edited: Mar 30, 2014
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