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**1. A 5kg block rests on a smooth plane inclined at an angle of 20degrees to the horizontal. The block is now pulled up the plane by a rope with a tension of 300N parallel to the plane for 10s.**

a) What is the acceleration during this period?

b) What is its speed at the end of this period?

c) How far does it travel during this period?

d) The rope snaps - how much further will the block travel up the slope?

e) What is the time interval between the rope snapping and the block returning to this point?

a) What is the acceleration during this period?

b) What is its speed at the end of this period?

c) How far does it travel during this period?

d) The rope snaps - how much further will the block travel up the slope?

e) What is the time interval between the rope snapping and the block returning to this point?

## Homework Equations

F=ma

v=u+at

s=0.5(u+v)t

**3.**

a) F=ma. The force is given but do I need to calculate mgsin(theta). I have a force but do not have velocity so cannot use v=u+at to find acceleration for the time period. Using F=ma I get F/m=a = 300N/5kg= 60ms^-2.

b) v=u+at 0+60ms^-2x10s =600ms^-1

c) distance=speed x time = 600ms^-1 x 10s = 6000m

Am I on the right track?

a) F=ma. The force is given but do I need to calculate mgsin(theta). I have a force but do not have velocity so cannot use v=u+at to find acceleration for the time period. Using F=ma I get F/m=a = 300N/5kg= 60ms^-2.

b) v=u+at 0+60ms^-2x10s =600ms^-1

c) distance=speed x time = 600ms^-1 x 10s = 6000m

Am I on the right track?