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Inclined Surface

  1. Oct 13, 2008 #1
    This is just a quick dumb question about a lab i had to do.. it involved putting a block on a piece of wood, and lifting the wood until the block moved. then we had to record the weight of the block and measure the angle that it took for the block to move...

    for a block that had a mass of 0.156kg, it moved at 55 degrees.
    i calculated the x component to be 1.25, and the y componenet to be 0.877. the force N(N) to be 0.877... but then it asks for f(N).. what is f(N)? how should i approach it.
  2. jcsd
  3. Oct 13, 2008 #2
    You should take into account the direction of the sin and cos and make a diagram.
    Sum the forces is the x and y directions:
    ΣFx: F(N)*sin(Θ)=+0
    ΣFy: F(N)*cos(Θ)-mg=+0
    Hope this helps. Sorry for the edits.
    Last edited: Oct 13, 2008
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