I am having a few issues reconciling Bernoulli's principle and the continuity equation for an incompressible flow in a horizontal funnel where there is significant difference in the area from the start to the end. More specifically, I want to work out exactly what the fluid is doing once it reaches the narrowest point. Opening of funnel: radius 10m, fluid flow at 1m/s Narrowest point: radius 1m, fluid flow x Fluid density is 1000kg/m3, fluid pressure ~200kPa and there is constant fluid flow into the funnel. If I use A1V1 = A2V2, I get a flow x of 100m/s However, if I use Bernoulli's principle of v2/2 + p/ρ = constant, and substitute in the values from the previous equation, I wind up with a really negative pressure. Now, I understand that the fluid would begin to spin in the funnel - so my guess is that 100m/s is not horizontal flow but incorporates the distance traveled while spinning. Furthermore, I would guess that the pressure cannot drop below 0. As such, I am arriving at an answer that the fluid would flow horizontally at ~20m/s, at close to 0 pressure, with any one fluid molecule that is located toward the edge of the funnel travelling at a speed of 100m/s. Helping me understand this all would be fantastic; but if not, the specific thing I am looking for is exactly what is happening to the fluid at the narrow point of funnel e.g. horizontal speed, rotational speed, velocity of the fluid at the edge of the funnel, fluid pressure. Thanks for any help you can provide.