Indcidence Matrices: Answer to Floor Paths Question is 14, Not 31?

[John112]

Should the right answer to this question(below) be 14 and not 31? because
A$_{ij}$$^{k}$ means number of paths from i to j of length K. So A$_{12}$$^{8}$ = 14

We then represent the graph as indcidence matrices and go from there on:

A = { {0,1,0,0}, {1,0,1,0}, {1,1,0,1}, {1,0,0,0} }

A[itex]^{8} = { {22,14,13,4}, {31,35,14,13}, {40,31,22,10}, {10,13,4,5} }

QUESTION:
At each step the elevator is able to travel directly from floor to floor as listed below. Suppose we go floor to floor eight times (e.g 1 to 2 then 2 to 3 would be two times). How many different ways can we start at floor 1 and end at floor 2?

floor 1 to floor 2
floor 2 to floor 3
floor 3 to floor 4
floor 4 to floor 1
floor 2 to floor 1
floor 3 to floor 1
floor 3 to floor 2


Correct Answer in the back of the book: 31

 

[Ray Vickson]

Should the right answer to this question(below) be 14 and not 31? because
A$_{ij}$$^{k}$ means number of paths from i to j of length K. So A$_{12}$$^{8}$ = 14

We then represent the graph as indcidence matrices and go from there on:



A$^{8} =$

QUESTION:
At each step the elevator is able to travel directly from floor to floor as listed below. Suppose we go floor to floor eight times (e.g 1 to 2 then 2 to 3 would be two times). How many different ways can we start at floor 1 and end at floor 2?

floor 1 to floor 2
floor 2 to floor 3
floor 3 to floor 4
floor 4 to floor 1
floor 2 to floor 1
floor 3 to floor 1
floor 3 to floor 2


Correct Answer in the back of the book: 31

I would not call the book's answer "correct"; I get exactly the same $A^8$ answer as you.

 

[John112]

I would not call the book's answer "correct"; I get exactly the same $A^8$ answer as you.

I guess they mixed it up then, I guess 31 is the answer from floor 2 to floor 1 then. Thanks for the reply.

 

[haruspex]

I agree. Quibble: the matrix is the adjacency matrix, not the incidence matrix, right?