Hi, I'm having trouble finding the indefinite integral of an equation.
The function is (2x-13)/[(x^2-2x+4)^0.5]
The Attempt at a Solution
I thought it was a good idea to let u=x^2-2x+4, hence du/dx= 2x-2.
From that I got [-11/(u^0.5)].du but evaluating this gives me -22(u^0.5), which I don't beleive is right.
Did I make a silly mistake or is my approach completely wrong? I am also having similar trouble finding the integral of [1+(1/t)]^5/(t^2).
Any help or advice would be very much appreciated, thank you.