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Indefinite Integral Problem

  1. Sep 3, 2015 #1
    • Member warned about posting without the template
    IMG_8357.jpg

    I have posted my attempt and the problem above. Please help!

    Thanks in advance!
     
  2. jcsd
  3. Sep 3, 2015 #2

    SteamKing

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    It's hard to mark up an image. :frown:

    The factor of (1/2) multiplies not only ∫ 1 dx but also ∫ -cos 6x dx, which you omitted from the second integral. :frown:

    After you have found the correct integrals, you can use the double angle formulas to convert these from trig functions in 6x to trig functions in 3x. :wink:
     
  4. Sep 3, 2015 #3
    So if I put - (1/12) in front of the sin6x it would be correct?
     
  5. Sep 3, 2015 #4

    SteamKing

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    Yesss...multiplication distributes over addition and subtraction.
     
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