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It is ψ(x,t)= [b^2-(x-vt)^2]^(-2) . I must integrate it with respect to x .

Thanks in advance for any help!

PD: I tried x-vt = u like the first step du=dx. My teacher adviced to me continue with [b^2-u^2]^(-2) = z but I don't know how to continue in the best way.