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Indefinite integral

  1. Oct 30, 2011 #1
    Hello, I need help with a very hard integral, I was trying several steps and I tried in the software "derive" but the answer didn't like to me.

    It is ψ(x,t)= [b^2-(x-vt)^2]^(-2) . I must integrate it with respect to x .

    Thanks in advance for any help!

    PD: I tried x-vt = u like the first step du=dx. My teacher adviced to me continue with [b^2-u^2]^(-2) = z but I don't know how to continue in the best way.
     
  2. jcsd
  3. Oct 31, 2011 #2
    Find A, B, C , D so that :
    1/(b²-u²)² = A/(b+u) +B/(b-u) +C/(b+u)² +D/(b-u)²
    Then you can easily integrate.
     
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