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Indefinite Integral

  1. Dec 4, 2011 #1
    I'm having a problem with the following integral: x^3/sqrt[1 + x^2] dx

    Can this be done with substitution or integration by parts?
    Throw me some hints at this one please!

    Sorry I forgot to include my attempt.

    I tried solving this by substitution, letting u=1-x^2. Then letting (-1/2)du = xdx. Simplifying it down and came to the answer of 1/3(1-x^2)-sqrt(1-x^2) + C
     
    Last edited: Dec 4, 2011
  2. jcsd
  3. Dec 4, 2011 #2
    Please make an attempt at the solution, or this thread will be deleted.
     
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