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I'm having trouble showing that is true other than showing a counter example when it doesn't work, namely when v1=1,v2=0, and v3=1.

TIA.

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I'm having trouble showing that is true other than showing a counter example when it doesn't work, namely when v1=1,v2=0, and v3=1.

TIA.

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matt grime

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matt grime

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in any 1 or 2-d vector space three vectors are always linearly dependent and the conditions on the paris are neither here nor there. ie it is trivillay true.

in 3 or more dimensions then there are 3 dependent vectors that are pariwise linerly independent and there are 3 vector that are L.I. that are nec. pariwise independent so the theorem is false.

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HallsofIvy

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Do you mean notphysicsss said:

I'm having trouble showing that is true other than showing a counter example when it doesn't work, namely when v1=1,v2=0, and v3=1.

TIA.

If the point was to show that {v

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