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Indeterminate forms

  1. Feb 5, 2009 #1
    I know [tex] \lim_{n \rightarrow \infty} (1 + 1/n)^n = \lim_{n \rightarrow \infty} 1^{\infty} [/tex], which is an indeterminate form, converging to e in this case. But what if the original sequence is [tex] a_n = 1^n [/tex]. Then as n tends to infinity, the function converges to 1 (because it's constant and the limit of a constant function is any term of the sequence). Is my reasoning correct here?


    EDIT: The original sequence is (1 + 1/n)^n, I messed up my latex.
     
  2. jcsd
  3. Feb 6, 2009 #2

    arildno

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    Yes, you are correct.
     
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