- #1
PFStudent
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Homework Statement
Given,
[tex]
{{(x - 7)}^{2}} + {{(y - 3)}^{2}} = {{8}^{2}}
[/tex]
What is,
[tex]
max(3x+4y)
[/tex]
Homework Equations
None really.
The Attempt at a Solution
Letting,
[tex]
3x+4y = C
[/tex]
When I get to the point where I have,
[tex]
{y} = {{\frac{-3x}{4}}+{\frac{C}{4}}}
[/tex]
Then substitute that in to,
[tex]
{{(x-7)}^{2}} + {{(y-3)}^{2}} = {{8}^{2}}
[/tex]
I get,
[tex]
{{\left(x - 7\right)}^{2}} + {{\left({\left({{\frac { - 3x}{4}} + {\frac {C}{4}}}\right)} - 3\right)}^{2}} = {{8}^{2}}
[/tex]
However, I am not sure how to proceed from here since I have two unknowns: [itex]x[/itex] and [tex]C[/tex].
So, how do I proceed from here?
Thanks,
-PFStudent
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