# Induced Current in a Circuit

1. Nov 3, 2008

### Tekmachine

1. The problem statement, all variables and given/known data
A two-loop wire circuit is 53.4069 cm wide
and 35.6046 cm high. The wire circuit in
the figure is located in a magnetic field whose
magnitude varies with time according to the
expression B = (0.001 T/s) t and its direction
is out of the page.

Assume The resistance per length of the
wire is 0.113 Ohm/m.

When the magnetic field is 0.2 T, find the
magnitude of the current through middle leg
PQ of the circuit. Answer in units of μA.

2. Relevant equations
$$\mathcal{E} = -A\frac{dB}{dt}$$

$$\mathcal{E} = I R$$

3. The attempt at a solution
$$\mathcal{E} = -(0.356046m)(0.356046m)(0.001T/s) = -1.267687541\times 10^{-4} v$$

$$\mathcal{E} = -(0.178023m)(0.356046m)(0.001T/s) = -6.338437706\times 10^{-5} v$$

$$\frac{(-1.267687541\times 10^{-4}v) - (-6.338437706\times 10^{-5}v)}{0.113}$$ = -560.92 μA

I might have messed up on the signs, and also I'm not sure how "When the magnetic field is 0.2 T" applies to my equations.