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vertyu
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Homework Statement
As shown in this picture:
a 18 cm long solenoid with 1500 loops (N = 1500) and radius 2 cm is located at the center of wire frame (coil) that is 5(width) by 8(height) cm. There is a current inside of solenoid that is growing from 0 to 2.5 A in 7.5 seconds that rotates counter clock wise. The frame is tilted and there is 70° angle between the frame and the axis of the solenoid.
Find the induced voltage in the frame.
Homework Equations
[tex]|\mathcal{E}| = \left|{{d\Phi_B} \over dt}\right|[/tex]
B = µnI, n = N/h
Phi = AB
The Attempt at a Solution
First I find magnetic Flux = A * µnI:
Phi = (Pi * 0.02^2) * (µ * (1500/0.18m) * 2.5A) = 3,28997e-5 Wb
emf = dPhi/dt
emf = 3,28997e-5 Wb/7.5s = 4.39 V
The way I understand it, the size of the frame, 5 by 8 cm doesn't affect the induced current, since the only source of the magnetic flux is the solenoid and it is located completely inside of the wire frame. Neither does the angle of the frame have effect in this case, since all the magnetic flux is passed through the fire frame. Is that correct?
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