An aluminum ring of radius 5 cm and resistance 0.003 ohms is placed around the center of a long air-core solenoid with 1000 turns per meter and a smaller radius of 3 cm. If the current in the solenoid is increasing at a constant rate of 270 A/s, what is the induced current in the ring? B= [tex] \mu*n*I [/tex] change in B/change in time = [tex]\mu[/tex] n *change in current/change in time = [tex] 4 \pi e-7)(1000)(270) [/tex] = .339 then change in flux/change in time= A*change in B/change in t A= [tex] \pi*r^2 [/tex] So A= (.03)^2 *3.14 then multiply that by .339 to get 9.58 e -4. Then I divided this by 3 e -4 to get the current and found that it was 3.19.. which wasn't right.. can someone please help me? Thanks in advance!