Can electric field be induced at a point near a time varying uniform magnetic field? "Near" means not the in the place where magnetic field exist. But at a point outside the field's presence.
You can induce electric fields everywhere. Why do you expect that it would not be possible somewhere?
You probably meant 'by a magnetic field, but not in the place where the magnetic field exists. A time varying magnetic field will have time varying vector potential [tex]\frac{\partial{\bf A}}{\partial t}[/tex] that can exist beyond the field, and induce an E field. This is like the 'Aharonov-Bohm' effect.
Yes. Say, for example, there's a long solenoid with a time-varying current I(t) running through it. The resulting magnetic field is nonzero only inside the solenoid. However, (assuming ∂B/∂t isn't zero) the electric field induced will also be nonzero outside of the solenoid.
Only in areas where there is a changing magnetic field. ∂B/∂t ≠ 0 implies that there is a magnetic field (apart from some specific points in time maybe).
Take a circular area beyond the region of changing magnetic field,but it should include changing magnetic field area then E.2∏R=-∏r^{2}.∂B/∂t,E is induced in region beyond WHERE B changes.
B= curl A. Apply Stokes' theorem for a B field in a solenoid. This gives an A outside the solenoid, where there is no B.
I don't see how your quote and your post are related. You can get a non-zero A everywhere if you like - even in a perfect vacuum, as you have gauge freedom. But you do not get an electric field without a changing magnetic field or some charge distribution.
Yes, but only inside the solenoid. The electric field it produces also "exists" (is nonzero) outside the solenoid where B=0.
Sorry, but what you want just violates the laws of physics. $$curl(B)=\frac{1}{c}\frac{\partial E}{\partial t} + \frac{4\pi}{c} j$$ You do not want currents and no magnetic field? => electric field is time-invariant. You cannot switch it on or off. This means that a time-independent charge distribution (which might consist of moving charges) is the only relevant option for a source of an electric field.
No, it certainly doesn't. If there's a long solenoid of radius a and turn density n with a current I(t) running through it, it will induce a magnetic field B(t)=μ_{0}nI(t) inside the solenoid. Outside of the solenoid B=0 everywhere. Evaluating the integral ∫E∙ds=-∂/∂t ∫B∙dA ⇔ E=-μ_{0}na^{2} I'(t) / 2r Even though B=0 outside the solenoid, it still produces a nonzero E outside the solenoid.
Transformers violate laws of physics? You learn something new every day! Sorry, I shouldn't be mean about it. It is a bit counter-intuitive. But yeah, if you take an infinitely-long solenoid, the magnetic field is ONLY present inside the solenoid. Yet you can wrap another solenoid around it, and induce a current on it by time-varying the current on the inner-solenoid. The B-field outside remains zero, but E-field is non-zero. This all has to do with curl of the electric field being governed by ∂B/∂t. Outside of the solenoid, both curl and divergence of E is zero, but it doesn't mean that the field itself is zero. Feel free to verify that circular E field with 1/R intensity satisfies conditions of both curl and divergence being zero. (In other words for [itex]E = E_0\frac{\hat{\phi}}{r}[/itex], [itex]\nabla \cdot E = 0[/itex] and [itex]\nabla \times E = 0[/itex] everywhere except r=0.)
I have shown in post no.6 that even outside a solenoid if one take a circular area and if it encloses the region of changing magnetic field then electric field will be induced at far distances also.
Ah ok, you are right. So we need a coil of infinite length, where B(t) changes linear in time. This gives a constant (in time), circular E(t) and no magnetic field outside.