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Induced emf

  • Thread starter airkapp
  • Start date
  • #1
54
0
A 7.2 cm diameter loop of wire is initially oriented perpendicular to a 1.3 T magnetic field. It is rotated so that its plane is parallel to the field direction in .20 s. What is the average induced emf in the loop?

A = πr2

A = π*.001 = .004 m

ФB = BA

= (1.3T)(.004m) = 5.2E-3 Wb

ФB / t = 0-5.2E-3 Wb / .20 s

= -2.6E-2 Wb/s

€ = -(1)( -2.6E-2 Wb/s)

= 2.6E-2 V


I think i messed up in my area of my formula. can someone help me out here.
 

Answers and Replies

  • #2
futb0l
I don't see any trig functions there... because the loop is rotated, there has to be a change in the dot product of the vectors.

Remember that A . B = |A| |B| cos theta
 
  • #3
futb0l
Now that I think about it - can't you just take BA/t and then times it by 1/root(2) to get the root mean square voltage.
 

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