A conducting square frame of side a and a long straight wire carrying current I and located in the same plane as shown in the figure. The frame moves to the right with a constant velocity v. The emf induced in the frame will be proportional to
The Attempt at a Solution
My teacher solved this in following manner
EMF induced in one side =B1vl
EMF induced in the other side=B2vl
EMF in the frame=B1vl - B2vl
Since B1∝1/r.I don't understand from where the below formula is coming?
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