1. The problem statement, all variables and given/known data In the following figure(Figure 1) switch S1 is closed while switch S2 is kept open. The inductance is L = 0.360 H, the resistance is R = 31.0 Ω , and the emf of the battery is 22.0 V . At time t after S1 is closed, the current in the circuit is increasing at a rate of di/dt = 7.20 A/s. At this instant what is Vab, the voltage across the resistor? 2. Relevant equations Emf = L * di/dt Kirchhoff's law V= IR 3. The attempt at a solution I tried to get the emf in the inductor and add it to the 22v given, but that didn't work. should i add the current (22/31 A) to the change in current integrated? I would get 7.2t + 22/31.