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Inductance of inductor

  1. May 2, 2007 #1
    1. The problem statement, all variables and given/known data

    a non inductive resistor passes a current of 20A rms, when connected to a 100v rms supply (50HZ). When connect in series with a pure inductor across a 230v supply the combination draws a current of 15A calculate impedance of the circuit, inductance of the inductor

    3. The attempt at a solution

    R = 100v/20A = 5 ohms

    Z = V/I

    Z = 230/15 = 15.3

    z = square root R^2 + X^2 Find X^2

    Z^2 - R^2 = X^2

    SRoot 15.3^2 - 5^2 = 14.45 ohms

    From what I found how do I find the inductance of the inductor. I only know one way using flux density but there is no data given on this in the question.
  2. jcsd
  3. May 2, 2007 #2
    I know that the formula for reactance is Xl = 2(pi) f L
    How do I find L thats the just of what I want.
  4. May 2, 2007 #3


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    You know that [tex]X_L = 14.45\Omega[/tex] anf f = 50Hz.
  5. May 3, 2007 #4
    Do yous get 21.7 for L
  6. May 3, 2007 #5


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    I found 0.0458H
  7. May 4, 2007 #6
    How did you get that
  8. May 4, 2007 #7


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  9. May 4, 2007 #8
    I see I made a substitution mistake in my forumla I devided by XL thanks for the help
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