1. Inductor & Resistor connected in series A circuit comprising of an Inductor & Resistor connected in series. The values are: R1 resistor Value 680Ω Resistance of the Inductor's Windings: (R of L) 98.2Ω Supply Voltage: 13.2V Circuit Current: 8.1mA Supply Freq: 50Hz Voltage across the resistor R1 5.5V Voltage across the inductor 10.4V Questions: 1. Use Ohm's Law to find the voltage dropped across the resistance of the inductor's windings (R of L) 2. Add this value to the voltage dropped across the resistor R1 3. Draw a scaled phasor diagram of the resistive voltage and the supply voltage, to find the voltage dropped across the pure inductance. My solution so far: 1. = 8.1mA * 98.2Ω = 0.8V Voltage dropped across R1 = 8.1mA * 680Ω = 5.5V 2. = 0.8V + 5.5v = 6.3V 3. This is where I get stuck Can anyone Help!!!!